(1/243)^2x-1=(1/9)^3x-2

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Solution for (1/243)^2x-1=(1/9)^3x-2 equation:



(1/243)^2x-1=(1/9)^3x-2
We move all terms to the left:
(1/243)^2x-1-((1/9)^3x-2)=0
Domain of the equation: 243)^2x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 9)^3x-2)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+1/243)^2x-((+1/9)^3x-2)-1=0
We calculate fractions
9^3x/243^2x*9)^3x-2))+(-243^2x/243^2x*9)^3x-2))-1=0
We can not solve this equation

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